Answer:

No. The bits in value provide data for format() when it creates a string of characters, but the bits in value are not changed.

Decimal Separator

If you want six digits to the right of the decimal point, use this DecimalFormat constructor:

DecimalFormat numform = new DecimalFormat("0.000000"); 

The "0.000000" is a pattern that says you want at least one digit in the integer part of the output string, followed by a decimal separator, followed by six digits. Each 0 stands for one digit in the output string. A zero will be replaced by a digit 0 through 9, as appropriate. Here is a complete program.

import java.text.*;

class IODemoThird
{
  public static void main ( String[] args )
  {
    DecimalFormat numform = new DecimalFormat("0.000000"); 
    System.out.println( "Third = " + numform.format(1.0/3.0) );
  }
}

If a big number needs more digits to the left of the decimal separator than the pattern of 0s show, they will all be output. This avoids producting misleading output.

QUESTION 3:

What does the following fragment write?

DecimalFormat numform = new DecimalFormat("0.00"); 
System.out.println( "Num = " + numform.format(13.456) );